int *pInt1 = new int[0]; int *pInt2 = new int[0]; int *pInt3 = new int[0];
The following expression is true:
((pInt1 != pInt2) && (pInt2 != pInt3) && (pInt3 != pInt1) )
This is described by the C++ standard.
Reference: More Exceptional C++
int *pInt1 = new int[0]; int *pInt2 = new int[0]; int *pInt3 = new int[0];
((pInt1 != pInt2) && (pInt2 != pInt3) && (pInt3 != pInt1) )
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