C++11: Algorithms: all_of, any_of, none_of

Given first and last iterators and a predicate, you can test to see if all, any or none of the elements in a container satisfies the predicates. Here is an example:

#include <algorithm>
#include <iostream>
int main()
{//                 0  1  2  3  4
  int allOnes[]  = {1, 1, 1, 1, 1};
  int someOnes[] = {1, 1, 1, 1, 0};

  int * beginIter = &allOnes[0];
  int * endIter   = &allOnes[5];

  bool allAreOnes = std::all_of  (beginIter, endIter,
                                  [](int element) {return element == 1;});
  std::cout << allAreOnes << " ";

  bool someAreOnes = std::any_of (beginIter, endIter,
                                  [](int element) {return element == 1;});
  std::cout << someAreOnes << " ";

  bool noneAreOnes = std::none_of(beginIter, endIter,
                                  [](int element) {return element == 1;});
  std::cout << noneAreOnes << " : ";

  beginIter = &someOnes[0];
  endIter  = &someOnes[5];

  allAreOnes = std::all_of  (beginIter, endIter,
                             [](int element) {return element == 1;});
  std::cout << allAreOnes << " ";

  someAreOnes = std::any_of (beginIter, endIter,
                             [](int element) {return element == 1;});
  std::cout << someAreOnes << " ";

  noneAreOnes = std::none_of(beginIter, endIter,
                             [](int element) {return element == 1;});
  std::cout << noneAreOnes << " ";

  return 0;
}
// Output: 1 1 0 : 0 1 0

Reference: https://isocpp.org/wiki/faq/cpp11-library-stl#cpp11-algorithms